Another math logic question.?
Ok so there’s this commuter lady. She arrives at the train station at 5 p.m. Her husband arrives just in time to pick her up ( @ 5). One day she arrived at the train station at 4 p.m. It was a pleasant day out so she decided to not phone her husband and walk home on the route he uses to pick her up. Some time when she was walking she met her husband and hopped in the car, turned around and headed home. When she got home she checked the clock and saw that she arrived 10 min. earlier than she usually would when her husband picked her up at 5. Suppose the husband left the house at the same time he usually picks her up at 5 and drives at a constant speed. How long did the wife have to walk until she met her husband ( in min.)?
5 minutes.
To see the solution, consider the situation from the husband’s point of view. He drives along till he sees his wife, picks her up and drives back home, arriving 10 minutes earlier that usual. The only part of the drive that he didn’t do was from the point where he picked his wife up to the train station and from the train station to the point where he picked up his wife. Since he was driving at a constant speed, we can assume that those two components were the same amount of time. How much time did he save in his drive? 10 minutes. Dividing it equally between the two parts, he saved 5 minutes on each leg, so his wife must have walked 5 minutes before he met her on the way.
OK Commuter
